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Old Thu May 17, 2012, 10:56am
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Quote:
Originally Posted by AllPurposeGamer View Post
Rule 9, Section 1

Art. 3...After the ball is placed at the disposal of a free thrower:

g. A player occupying a marked lane space may not have either foot beyond the vertical plane of the outside edge of any lane boundary, or beyond the vertical plane of any edge of the space (2 inches by 36 inches) designated by a lane-space mark or beyond the vertical plane of any edge of the space (12 inches by 36 inches) designated by a neutral zone. A player shall position one foot near the outer edge of the free-throw lane line. The other foot may be positioned anywhere within the designated 36-inch lane space.
Obviously I'm not an official and I'm not accustomed to reading rules like this, but I am not understanding this rule at all. "The verticle plane of the outside edge of any lane boundry"? Where would I find this verticle plane?
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Old Thu May 17, 2012, 10:58am
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Quote:
Originally Posted by davecasper View Post
Obviously I'm not an official and I'm not accustomed to reading rules like this, but I am not understanding this rule at all. "The verticle plane of the outside edge of any lane boundry"? Where would I find this verticle plane?

Perpendicular to the playing surface.

MTD, Sr.
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Last edited by Mark T. DeNucci, Sr.; Thu May 17, 2012 at 11:36am. Reason: Corrected spelling
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Old Thu May 17, 2012, 10:59am
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Quote:
Originally Posted by davecasper View Post
Obviously I'm not an official and I'm not accustomed to reading rules like this, but I am not understanding this rule at all. "The verticle plane of the outside edge of any lane boundry"? Where would I find this verticle plane?
Where the outside edge & inside edge of any lane boundary meet.

The rationale for this is an attempt to remove rough play on FT rebounding.
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Old Thu May 17, 2012, 11:13am
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So as long as his back foot is within 3 feet from the lane he is ok then?
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