70' base distance

[MD Longhorn]

Originally Posted by celebur

Simple trigonometry. For a right-angle triangle:
c^2 = a^2 + b^2 (where c is the hypotenuse and a & b are the other two sides)

For a ball diamond, c = distance to 2B, and a = b = base distance.

So c = SQRT(70^2 + 70^2)

No need for the rule book.

Yes, but not a lot of people realize the bases do not actually form the inside corners of a perfect square - 3 bases do, but 2nd base doesn't. If it did, you're answer would be wrong.

98 feet, 11 and 15.0304 sixteenths inches.