Quote:
Originally Posted by celebur
Simple trigonometry. For a right-angle triangle:
c^2 = a^2 + b^2 (where c is the hypotenuse and a & b are the other two sides)
For a ball diamond, c = distance to 2B, and a = b = base distance.
So c = SQRT(70^2 + 70^2)
No need for the rule book.
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I considered the right triangle approach, but recalled that 2nd base isn't fully inside the diamond.
I thought this was geometry, BTW.
In any case, the diameter of a spike being driven to measure the distance(s) is enough to convince me to remember this distance as a skosh short of 99'.
Thanx for the replies and bringing back the nightmares of HS math!
