70' base distance

[Tru_in_Blu]

Originally Posted by celebur

Simple trigonometry. For a right-angle triangle:
c^2 = a^2 + b^2 (where c is the hypotenuse and a & b are the other two sides)

For a ball diamond, c = distance to 2B, and a = b = base distance.

So c = SQRT(70^2 + 70^2)

No need for the rule book.

I considered the right triangle approach, but recalled that 2nd base isn't fully inside the diamond.

I thought this was geometry, BTW.

In any case, the diameter of a spike being driven to measure the distance(s) is enough to convince me to remember this distance as a skosh short of 99'.

Thanx for the replies and bringing back the nightmares of HS math!