clock stop end of game question?

[lpbreeze]

I saw a shot made with a little over a second to go. When does the clock stop then? Once it goes through the net? hits the floor? Time ran out and the game was over but I was thinking perhaps if the clock had stopped there would be .5 seconds left.

[ca_rumperee]

Originally Posted by lpbreeze

I saw a shot made with a little over a second to go. When does the clock stop then? Once it goes through the net? hits the floor? Time ran out and the game was over but I was thinking perhaps if the clock had stopped there would be .5 seconds left.

Word.

[BktBallRef]

Originally Posted by ca_rumperee

Word.

Wouldn't that lead you to believe he's talking about a college game?

The clock stops when the ball clears the net, lpbreeze.

[eg-italy]

Originally Posted by lpbreeze

I saw a shot made with a little over a second to go. When does the clock stop then? Once it goes through the net? hits the floor? Time ran out and the game was over but I was thinking perhaps if the clock had stopped there would be .5 seconds left.

It depends on the rule set used in the game. In FIBA the clock should be stopped as soon as the basket is made, i.e. when the ball goes through the net (well, also if it stops in the basket, a very rare event nowadays), if we are in the last two minutes of the fourth period or overtime.

I believe that in NFHS the clock doesn't stop on a made basket.

Ciao

[Mark Padgett]

Originally Posted by eg-italy

well, also if it stops in the basket, a very rare event nowadays

Really? I thought that trapezoidal ball was always getting caught in the net.

[eg-italy]

Originally Posted by Mark Padgett

Really? I thought that trapezoidal ball was always getting caught in the net.

That's envy because we know more geometrical figures than you.

Do you know how to compute the area of a trapezoid (in the US sense, I learnt now from a dictionary that the meanings of trapezoid and trapezium are exchanged from British English to American English ) if the bases are given in yards and feet and the height in inches?

Ciao

[biz]

ok I'll bite.

convert everything to the same unit of measure, then use the formula:

Altitude (A) x the average width ((b1 + b2) / 2)

[rainmaker]

Originally Posted by eg-italy

That's envy because we know more geometrical figures than you.

Do you know how to compute the area of a trapezoid (in the US sense, I learnt now from a dictionary that the meanings of trapezoid and trapezium are exchanged from British English to American English ) if the bases are given in yards and feet and the height in inches?

Ciao

I learned to call the geometric figure a trapezoid, and that the trapezium is a muscle in the palm of the hand.

[eg-italy]

Originally Posted by biz

ok I'll bite.

convert everything to the same unit of measure, then use the formula:

Altitude (A) x the average width ((b1 + b2) / 2)

Well, it's the conversion the problem, isn't it? Something like "how many feet in a mile?"

Ciao

[Back In The Saddle]

Originally Posted by eg-italy

Well, it's the conversion the problem, isn't it? Something like "how many feet in a mile?"

Ciao

5,280. Everybody knows that.

[biz]

fine then....

Convert the bases first to feet by multiplying the the Yards by 3 and adding any remaining feet. Then convert the feet to inches by multiplying by 12. Then use said formula.

Or...

convert the inches to feet by dividing by 12, and convert the yards to feet by, again, multiplying by 3.

btw...probably very confusing to those outside of the states and GB, but it's 4th grade math here.