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In the yearly packet we get from the NCAA 2001 - 2002 Officiating Program. Under the Shot clock situations, it talks about this play. Under D #6 it says that if it is simultainiously grabbed by both A and B then you have a reset. This is what I was saying in the earlier post. The key thing is who gets the ball first A or B or both at the same time.
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Dennis, is there any rationale given for that ruling? It seems to be at odds with the normal reset rules: 1) hit the rim; 2) defensive foul; 3) kick; 4) change of possession.
What's the reasoning behind this ruling? Is any given? Chuck |
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Chuck,
Here is logic behind new shot clock on this play. Rule 2-13.6.c The shot clock operator shall stop the timing device and reset it when a held ball occurs. (Exceptions as follow) Exc 2-13.7.d Stop the timing device and continue time without a reset when play begins under the following circumstances: During team control as defined in 4-13, a defensive player causes a held ball and the AP arrow favors the offensive team. Exc 2-13.7.g Stop the timing device and continue time without a reset when play begins under the following circumstances: After any technical foul..... this has nothing to do with the play in question. Under the first exception listed above, there must be team control. Since the airball was simultaneously possessed by both teams, this criteria was not met. Therefore there must be a reset of the shot clock. If Team A had momentarily possessed the shot and then was tied up by Team B, there would be no reset. |
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h . After a simultaneous held ball as described in Rule 7-4.1.g occurs during a throw-in and the alternating-possession arrow favors the throw-in team. which then refers to 7-4.1 The ball shall be awarded out of bounds after: g . A held ball as in Rule 4-35. Aargh!!! This refers to 4-35 Definition of held ball. Gotta love rule books! |
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