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Originally Posted by Fisk
I know this has been asked a million times.
Chalk it up to community service for those answering.
Runners on 1st (A) and 2nd. (B)
Ball hit to outfield and runners proceed towards 3rd and 2nd respectively.
Ball is overthrown and goes into dug out on the play.
Runner A reaches 2nd and Runner B reaches third before ball goes out of play.
Obviously Runner B gets to go home. The question is ...What base does Runner A who was past 2nd get?
Thanks... Also is there a link to offical baseball rules online?
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The award on a throw made by an outfielder is 2 bases from the time of the THROW. It has nothing to do with the position of the runners when the ball enters the dugout. So R2 scores. R1 will be awarded third unless he already reached second before the ball left the outfielder's hand, in which case he'd score, too.