Good Grief...

[rainmaker]

If someone doesn't put something interesting on this board pretty soon, I'm gonna have to quit procrastinating and go accomplish something!

[Dan_ref]

I thought this was pretty interesting



Just can't please some folks I guess...

[mxd]

Originally posted by Dan_ref

I thought this was pretty interesting



Just can't please some folks I guess...

The banana is awesome!! I can't get enough of it ..




Anyone see Team USA choke today?

[ChuckElias]

Originally posted by mxd
Anyone see Team USA choke today?

Yes, and it was absolutely pathetic. Unbelievable. A whole team of NBA players who can neither defend nor shoot the long jumper. It was terrible.

But not terribly interesting. Sorry Juulie.

[Jurassic Referee]

Originally posted by rainmaker
If someone doesn't put something interesting on this board pretty soon, I'm gonna have to quit procrastinating and go accomplish something!

Okay. Try this, but don't read the bottom line until you're done!

1) Pick the number of times a week that you would like to have chocolate(gotta be more than once but less than 10).
2) Multiply this number by 2.
3) Add 5.
4) Multiply it by 50 (wimmen can use a calculator).
5) If you have already had your birthday this year, add 1754.....If you haven't had your birthday yet,add 1753.
6) Now subtract the four digit year that you were born.

You should have a 3 digit number left.

The first digit of this number was your original number(how many times a week for chocolate).
The next two numbers are......

TaDa.....

YOUR AGE!!

NOTE: This is the only year that this will work.

[ref18]

Originally posted by Jurassic Referee

Okay. Try this, but don't read the bottom line until you're done!

1) Pick the number of times a week that you would like to have chocolate(gotta be more than once but less than 10).
2) Multiply this number by 2.
3) Add 5.
4) Multiply it by 50 (wimmen can use a calculator).
5) If you have already had your birthday this year, add 1754.....If you haven't had your birthday yet,add 1753.
6) Now subtract the four digit year that you were born.

You should have a 3 digit number left.

The first digit of this number was your original number(how many times a week for chocolate).
The next two numbers are......

TaDa.....

YOUR AGE!!

NOTE: This is the only year that this will work.

Wow!! That was pretty cool.

[Dan_ref]

Originally posted by Jurassic Referee

Okay. Try this, but don't read the bottom line until you're done!

1) Pick the number of times a week that you would like to have chocolate(gotta be more than once but less than 10).
2) Multiply this number by 2.
3) Add 5.
4) Multiply it by 50 (wimmen can use a calculator).
5) If you have already had your birthday this year, add 1754.....If you haven't had your birthday yet,add 1753.
6) Now subtract the four digit year that you were born.

You should have a 3 digit number left.

The first digit of this number was your original number(how many times a week for chocolate).
The next two numbers are......

TaDa.....

YOUR AGE!!

NOTE: This is the only year that this will work.

That's nuffin'. Ponder this:

http://www.caveofmagic.com/

[ChuckElias]

Originally posted by Dan_ref
That's nuffin'. Ponder this:

http://www.caveofmagic.com/

Nuffim', eh? That's too easy!

[mick]

The Town of Epoufette, MI in the U.P. received 5" of rain in 30 minutes on Monday. I filled 'er up there on Sunday.
mick

[TravelinMan]

JR and Dan - now that's entertainment!

Here's my contribution
There are 1000 rooms with thousands of solid gold coins in them. Each coin weighs 16 ounces, except in one of the rooms all the coins weigh only 15 ounces. Using a scale, WITH ONE WEIGHING ONLY, can you tell me which room contains the coins weighing 15 ounces? You can take any amount of coins from any of the rooms but you can only do ONE weighing.

OK math wizzes - tell me if this can be done and HOW you would do it.

[mick]

Originally posted by TravelinMan
JR and Dan - now that's entertainment!

Here's my contribution
There are 1000 rooms with thousands of solid gold coins in them. Each coin weighs 16 ounces, except in one of the rooms all the coins weigh only 15 ounces. Using a scale, WITH ONE WEIGHING ONLY, can you tell me which room contains the coins weighing 15 ounces? You can take any amount of coins from any of the rooms but you can only do ONE weighing.

OK math wizzes - tell me if this can be done and HOW you would do it.

One coin from room one, two coins from room two....

[ref18]

Anyone looking to listen to some good music??

If so check out my launch station.

http://launch.yahoo.com/lc/?rt=0&rp1=0&rp2=1232728982

I figure I may as well make some sort of contribution.

[TravelinMan]

Originally posted by mick

One coin from room one, two coins from room two....

Way to go Mick.......

[ref18]

Originally posted by Dan_ref

That's nuffin'. Ponder this:

http://www.caveofmagic.com/

That one scares me, I can't figure out how it works, and it freaks me out with how accurate it is.

[rainmaker]

Originally posted by ref18
[B]That's nuffin'. Ponder this:

http://www.caveofmagic.com/

That one scares me, I can't figure out how it works, and it freaks me out with how accurate it is. [/QUOTE]


I figured that out, but THIS is scary!!

Originally posted by mick
The Town of Epoufette, MI in the U.P. received 5" of rain in 30 minutes on Monday.