[jump stop]

Originally Posted by Rob1968

The context is established with the initial statement of4-44-3 . . . After coming to a stop and establishing a pivot foot: - which the player does at the 1:27 mark. Then, having moved the left foot rearward, she jumps (both feet leaving the floor) and alights on the left foot, before releasing the ball.
I agree that in real time, this move is rarely called a travel. A completely clean - legal - drop-step would involve the non-pivot foot being in contact with the floor, before the pivot foot is lifted. Indeed, if that is the case, until the pivot foot touches again, it cannot be a travel.
Yes, on a normal drive to the basket, at a run, both feet are off the floor three times, without the action incurring a travel violation.
This entire sdcenario is not the main subject of the OP, in as much as a jump-stop is quite a different move.

If this is true then it seems like every layup in which the person is running would be a travel because I have heard it is impossible to run and have both feet touch at the same time. Try running and have both feet on floor at same time. Look at layup shown on video at around 1:05 , pivot foot is lifted before left heel touches.