[slow whistle]

Originally Posted by bob jenkins

Sigh.

First, offset the number leaving the bench who don't fight. 2 for A is more than 1 for B, so A gets a penalty (one penalty only, here -- even if it was 10 for A and 1 for B, it's only one penalty)

Then, offset the number leaving and fighting. 0 for A, 1 for B == 1 penalty for B (here, it's one per difference -- if it was zero for A and 10 for B, it would be 10 penalties).

Do the same for Players fighting, and coaches leaving.

Then, offset the penalties across the categories.

1 penalty for A, 1 penalty for B == no FTs. (in the parenthetical example, it would be 1 penalty for A, 10 penalties for B == 18 FTs for A)

That's what I always thought Bob, but how do you explain casebook play 10.4.5 situation A c)? It says no free throws, go to POI and there are an uneven number of penalties?