Quote:
Originally Posted by Back In The Saddle
That's what I used to think as well. But that doesn't seem to square with Scrappy's case play ruling, in particular scenario c. In it you have two non-fighters leaving for A, a non-fighter and a fighter leaving for B. It would seem that A would get 4 free throws and B would get 2.
However, the ruling says: "No free throws are awarded for the simultaneous technical fouls as the number of bench personnel leaving the bench and the penalties are the same for both teams."
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Sigh.
First, offset the number leaving the bench who don't fight. 2 for A is more than 1 for B, so A gets a penalty (one penalty only, here -- even if it was 10 for A and 1 for B, it's only one penalty)
Then, offset the number leaving and fighting. 0 for A, 1 for B == 1 penalty for B (here, it's one per difference -- if it was zero for A and 10 for B, it would be 10 penalties).
Do the same for Players fighting, and coaches leaving.
Then, offset the penalties across the categories.
1 penalty for A, 1 penalty for B == no FTs. (in the parenthetical example, it would be 1 penalty for A, 10 penalties for B == 18 FTs for A)