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Originally Posted by SAump
Muddied over R2 passing R3 are the actions of R3 retreating past 3B. I would add to your argument that R3 cannot legally run back toward 2B by rule. Things may have been different between bases, but a rule prevents R3 from running back to 2B after legally obtaining 3B. That cannot happen. I would also add to your argument that as long as R2 has not passed 3B, then R2 cannot be considered past R3. Like you, I am not convinced that R2 has passed R3 in this situation. Therefore, I cannot rule R2 out for passing a preceeding runner.
I agree the playing action on R3 places R3 in "limbo" until action allows an umpire to make an out call on R3. As presented, R3 must be out by tag and R2 must be safe on 3B. If both runners are considered "safe on the same bag" and both are tagged, then by rule, R2 would be out ( I also agree with you) as the bag belongs to R3 by FED rule 8-2-7 and OBR 7-3.
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Are we going to see "limbo" defined in section 2 next year?
In the situation that began this thread Sa is right, R3 cannot return to 2nd, though it is not always the case. A runner can legally obtain a base then retreat to a previous base as long as the base is unoccupied and the pitcher has not assumed his pitching position.
The fact that R3 cannot legally retreat back to 2nd does not prevent him from being in the 2nd to 3rd baseline. IMHO
F2 is chasing R3 back to 3rd, R2 is on 3rd, R3 overruns 3rd directly down the line. The limbo theory, I think, considers R3 to be equal with R2 at this point, not behind. Therefore, theoretically speaking, R3 is on the bag. As F5 gets to the bag he tags R2, who is standing on the bag. Out or Safe?
Here is the key
R2 can only be safe if you deem R3 to be
ahead of R2 in the baseline. If R2 is equal to or ahead of R3 he is out.
I've got two outs and happy.