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Originally Posted by ref49873
Had this situation last night. Fed rules. Bases loaded no outs. B1 hits ball back to F1 who throws home for force out. None of the other runners attempt to advance, so F2 throws to F5 for force out at 3rd base. Now runner that was forced out at third didn't realize he was out and gets caught is rundown and is tagged out again. Same runner can't make two outs.
Should there be two outs or three for interference?
Thanks for you opinoins.
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The defense should know the situation. R3 going to home is out on the play at home (F1 thrown to F2 and the assumed touch of home and the umpires call of the out). F2 thew ball to F5 getting R2 out @ 3rd assuming the touch of 3rd. Now the rundown ensues, this is the defenses problem, if R1 makes it safely to 2nd and the B/R makes it to first. Don't kill this as it occurs. Once R3 is tagged out, don't signal the out here, he's already out.
On the flip side, a case could be made for interference on R3 getting caught in a rundown. However, since two outs were recorded on the play, I'd let let this slide, because of the quick 1st out being made on R3 at home, and your description that the runners did not realize how quick everything occurred.
Without seeing the actions of R3, specifically and intentionally wanting to get caught in a rundown to advance the runners beyond the bases they would have reached (R1 to 2nd and then 3rd,B/R to 1st and then 2nd). In this case, then you call R1 out on the interference, but this would be a huge stretch to award a tripple play. Let the DP go and get make sure the runners are at 1st & 2nd unless mitigating circumstances warrant runners at 2nd & 3rd.